x^2-48=4x^2+1

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Solution for x^2-48=4x^2+1 equation: 



x^2-48=4x^2+1

We move all terms to the left:

x^2-48-(4x^2+1)=0

We get rid of parentheses

x^2-4x^2-1-48=0

We add all the numbers together, and all the variables

-3x^2-49=0

a = -3; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·(-3)·(-49)
Δ = -588
Delta is less than zero, so there is no solution for the equation

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